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2r^2-75r-1008=0
a = 2; b = -75; c = -1008;
Δ = b2-4ac
Δ = -752-4·2·(-1008)
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13689}=117$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-117}{2*2}=\frac{-42}{4} =-10+1/2 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+117}{2*2}=\frac{192}{4} =48 $
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